armstrong number in java

Write a program to check given number is armstrong or not.

Example : 153

Armstrong number

class ArmstrongDemo {
  public static void main(String[] args) {


   int number = 153;
   int tempNumber = number;
   int newNumber = 0;


   while (tempNumber != 0) {
    int mod = tempNumber % 10;
    newNumber = newNumber + (mod * mod * mod);
    tempNumber = tempNumber / 10;
   }


   if (number == newNumber) {
    System.out.println(number + " is armstrong");
   } else {
    System.out.println(number + " is not armstrong");
   }


  }
}

Output: 153 is armstrong

Program to print all armstrong number between 0 to 500.

Armstrong number between 0 to 500

class AmstrongDemo{
  public static void main(String[] args) {
   for (int i = 0; i < 500; i++) {
    isArmstrongNumber(i);
   }
  }
  
  static void isArmstrongNumber(int number) {
   int tempNumber = number;
   int newNumber = 0;  
   while (tempNumber != 0) {
    int mod = tempNumber % 10;
    newNumber = newNumber + (mod * mod * mod);
    tempNumber = tempNumber / 10;
   }  
   if (number == newNumber) {
    System.out.println(number);
   } 
  }
}

Output: 

0

1

153

370

371

407